6T^(-1/3)=-(5/3)T^(2/3)

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Solution for 6T^(-1/3)=-(5/3)T^(2/3) equation: 


D( T )

T = 0

T = 0

T = 0

T in (-oo:0) U (0:+oo)

6*T^(-1/3) = -((5/3)*T^(2/3)) // + (5/3)*T^(2/3)

(5/3)*T^(2/3)+6*T^(-1/3) = 0

5/3*T^(2/3)+6*T^(-1/3) = 0

t_1 = T^(1/3)

5/3*t_1^2+6*t_1^-1 = 0

t_1^-1*(5/3*t_1^3+6) = 0

5/3*t_1^3 = -6 // : 5/3

t_1^3 = -18/5

t_1^3 = -18/5 // ^ 1/3

t_1 = -(18/5)^(1/3)

1/t_1 = 0

1*t_1^-1 = 0 // : 1

t_1^-1 = 0

t_1 należy do O

t_1 = -(18/5)^(1/3)

T^(1/3)+(18/5)^(1/3) = 0

1*T^(1/3) = -(18/5)^(1/3) // : 1

T^(1/3) = -(18/5)^(1/3)

( -(18/5)^(1/3) < 0 i 1/3 in (0:1) ) => T należy do O

T belongs to the empty set

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